Given a string s and a dictionary of words dict, determine if s can be break into a space-separated sequence of one or more dictionary words.
Example
Given s = "lintcode", dict = ["lint", "code"].
Return true because “lintcode” can be break as "lint code".
Version 1. DP 常规做法 无优化 straight forward
public boolean wordSegmentation(String s, Set < String > dict) {
if (s == null || dict == null) {
return false;
}
//result[i] means if s.subString(0,i+1) can be break.
boolean[] result = new boolean[s.length() + 1];
result[0] = true;
for (int i = 0; i < s.length(); i++) {
if (dict.contains(s.substring(0, i + 1))) {
result[i + 1] = true;
} else {
for (int j = 0; j < i; j++) {
if (result[j + 1] && dict.contains(s.substring(j + 1, i + 1))) {
result[i + 1] = true;
break;
}
}
}
}
return result[s.length()];
}
